Friday, 23 September 2016

Series Program : (1^1) + (2^2) + (3^3) + (4^4) + (5^5) + ... + (n^n)

(1^1) + (2^2) + (3^3) + (4^4) + (5^5) + ... + (n^n)
long power(int a, int b)
{
long i, p=1;
for(i=1;i<=b;i++)
{
p=p*a;
}
return p;
}

int main()
{
long i,n,sum=0;
n=5;
for(i=1;i<=n;i++)
{
sum=sum+power(i,i);
}
printf("Sum: %d",sum);
return 0;
}

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