Series Program : (1^1) + (2^2) + (3^3) + (4^4) + (5^5) + ... + (n^n)

(1^1) + (2^2) + (3^3) + (4^4) + (5^5) + ... + (n^n)

long power(int a, int b)
{
    long i, p=1;
    for(i=1;i<=b;i++)
    {
        p=p*a;
    }
    return p;
}

int main()
{
    long i,n,sum=0;
    n=5;
    for(i=1;i<=n;i++)
    {
        sum=sum+power(i,i);
    }
    printf("Sum: %d",sum);
    return 0;
}