Series Program : 1 3 8 15 27 50 92 169 311

1 3 8 15 27 50 92 169 311

void main()
{
    int a=1, b=3, c=4, n=10, sum, i;
    printf("%d %d ",a,b,c);
    for(i=4; i<=n; i++)
    {
        sum = a+b+c;
        printf("%d ",sum);
      a = b;
      b = c;
      c = sum;
    }
}

Series Program : 2 15 41 80 132 197 275 366 470 587

2 15 41 80 132 197 275 366 470 587

 

int main()
{
    int a=2,i,n=10;
    for(i=1;i<=n;i++)
    {
        printf("%d ",a);
        a+=13*i;
    }
    return 0;
}

Series Program : 1 2 3 6 9 18 27 54...

1 2 3 6 9 18 27 54...

int main()
{
    int a=1,b=2,i,n=10;
    printf("%d %d ",a, b);
    for(i=3;i<=n;i++)
    {
        if(i%2==1)
        {
            a=a*3;
            printf("%d ",a);
        }
        else
        {
            b=b*3;
            printf("%d ",b);
        }
    }
    return 0;
}

Series Program : 1/2 - 2/3 + 3/4 - 4/5 + 5/6 - ...... n

1/2 - 2/3 + 3/4 - 4/5 + 5/6 - ...... n

int main()
{
    double i, n,sum=0;
    n=10;
    for(i=1;i<=n;i++)
    {
        if ((int)i%2==1)
            sum+=i/(i+1);
        else
            sum-=i/(i+1);
    }
    printf("Sum: %lf",sum);
    return 0;
}

Series Program : [(1^1)/1] + [(2^2)/2] + [(3^3)/3] + [(4^4)/4] + [(5^5)/5] + ... + [(n^n)/n]

[(1^1)/1] + [(2^2)/2] + [(3^3)/3] + [(4^4)/4] + [(5^5)/5] + ... + [(n^n)/n]

long power(int a, int b)
{
    long i, p=1;
    for(i=1;i<=b;i++)
    {
        p=p*a;
    }
    return p;
}

int main()
{
    long i,n;
    double sum=0;
    n=5;
    for(i=1;i<=n;i++)
    {
        sum=sum+(power(i,i)/i);
    }
    printf("Sum: %lf",sum);
    return 0;
}

Series Program : (1!/1) + (2!/2) + (3!/3) + (4!/4) + (5!/5) + ... + (n!/n)

(1!/1) + (2!/2) + (3!/3) + (4!/4) + (5!/5) + ... + (n!/n)

long fact(int n)
{
    long i, f=1;
    for(i=1;i<=n;i++)
    {
        f=f*i;
    }
    return f;
}

int main()
{
    long i,n;
    double sum=0;
    n=5;
    for(i=1;i<=n;i++)
    {
        sum=sum+(fact(i)/i);
    }
    printf("Sum: %lf",sum);
    return 0;
}

Series Program : (1^1) + (2^2) + (3^3) + (4^4) + (5^5) + ... + (n^n)

(1^1) + (2^2) + (3^3) + (4^4) + (5^5) + ... + (n^n)

long power(int a, int b)
{
    long i, p=1;
    for(i=1;i<=b;i++)
    {
        p=p*a;
    }
    return p;
}

int main()
{
    long i,n,sum=0;
    n=5;
    for(i=1;i<=n;i++)
    {
        sum=sum+power(i,i);
    }
    printf("Sum: %d",sum);
    return 0;
}

Series Program : 1! + 2! + 3! + 4! + 5! + ... + n!

1! + 2! + 3! + 4! + 5! + ... + n!

long fact(int n)
{
    long i, f=1;
    for(i=1;i<=n;i++)
    {
        f=f*i;
    }
    return f;
}

int main()
{
    long i,n,sum=0;
    n=5;
    for(i=1;i<=n;i++)
    {
        sum=sum+fact(i);
    }
    printf("Sum: %d",sum);
    return 0;
}

Series Program : (1) + (1+2) + (1+2+3) + (1+2+3+4) + ... + (1+2+3+4+...+n)

(1) + (1+2) + (1+2+3) + (1+2+3+4) + ... + (1+2+3+4+...+n)

int main()
{
    int i,j,n,sum=0;
    n=10;
    for(i=1;i<=n;i++)
    {
        for(j=1;j<=i;j++)
        {
            sum+=j;
        }
    }
    printf("Sum: %d",sum);
    return 0;
}

Series Program : (1*1) + (2*2) + (3*3) + (4*4) + (5*5) + ... + (n*n)

(1*1) + (2*2) + (3*3) + (4*4) + (5*5) + ... + (n*n)

int main()
{
    int i,n,sum=0;
    n=10;
    for(i=1;i<=n;i++)
    {
        sum+=i*i;
    }
    printf("Sum: %d",sum);
    return 0;
}

series program : 1 + 2 + 3 + 4 + 5 + ... + n

1 + 2 + 3 + 4 + 5 + ... + n

int main()
{
    int i,n,sum=0;
    n=10;
    for(i=1;i<=n;i++)
    {
        sum+=i;
    }
    printf("Sum: %d",sum);
    return 0;
}